A sliver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 10 12 /sec. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver =108 and Avogadro number = 6.02 × 10 23 gm mole –1 )
Text Solution
Verified by ExpertsThe correct answer is:
D

⇒ k = 4 π 2 m × f 2
k =
=
= 7.1 N/m
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A mass M, attached to a horizontal spring, executes SHM with a amplitude A 1 . When the mass M pass…
Two particles are executing simple harmonic motion of the same amplitude A and frequency ꞷ along th…
If a simple pendulum has significant amplitude (up to a factor of 1/e of original) only in the peri…
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5s. In anothe…
A particle moves with simple harmonic motion in a straight line. In first τ s, after starting from …
For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE)…